2025-06-01

1133: For Diffeomorphism Between C Manifolds with Boundary and C Vectors Field over Domain, There Is Unique C Vectors Field over Codomain Map-Related with Vectors Field over Domain

<The previous article in this series | The table of contents of this series | The next article in this series>

description/proof of that for diffeomorphism between C manifolds with boundary and C vectors field over domain, there is unique C vectors field over codomain map-related with vectors field over domain

Topics


About: vectors space

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that for any diffeomorphism between any C manifolds with boundary and any C vectors field over the domain, there is the unique C vectors field over the codomain map-related with the vectors field over the domain.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Structured Description


Here is the rules of Structured Description.

Entities:
M1: { the C manifolds with boundary }
M2: { the C manifolds with boundary }
f: :M1M2, { the diffeomorphisms }
V1: { the C vectors fields over M1}
//

Statements:
!V2{ the C vectors fields over M2}((V1,V2){ the f -related vectors fields pairs })
//


2: Proof


Whole Strategy: Step 1: define V2 as :M2TM2,mdff1(m)V1(f1(m)); Step 2: see that V2 is C; Step 3: see that V2 is unique.

Step 1:

Let us define V2:M2TM2,mdff1(m)V1(f1(m)).

Step 2:

V2=dfV1f1, where df:TM1TM2 is the global differential of f.

f1 is C, V1 is C, and df is C by the proposition that for any C immersion between any C manifolds with boundary, its global differential is a C immersion: any diffeomorphism is a C immersion.

So, V2 is C, by the proposition that for any maps between any arbitrary subsets of any C manifolds with boundary Ck at corresponding points, where k includes , the composition is Ck at the point.

Step 3:

V2 is unique, because for each mM2, f(f1(m))=m, so, there is no other option but V2(m)=dff1(m)V1(f1(m)).


References


<The previous article in this series | The table of contents of this series | The next article in this series>