2024-02-11

475: For Maps Between Arbitrary Subsets of C Manifolds with Boundary Ck at Corresponding Points, Composition Is Ck at Point

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description/proof of that for maps between arbitrary subsets of C manifolds with boundary Ck at corresponding points, composition is Ck at point

Topics


About: C manifold

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that for any maps between any arbitrary subsets of any C manifolds with boundary Ck at corresponding points, where k includes , the composition is Ck at the point.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Structured Description


Here is the rules of Structured Description.

Entities:
M1: { the C manifolds with boundary }
M2: { the C manifolds with boundary }
S1: { the subsets of M1}
S2: { the subsets of M2}
S2: { the subsets of M2}, such that S2S2
S3: { the subsets of M3}
p: S1
k: N{}
f1: :S1S2, { the maps Ck at p}
f2: :S2S3, { the maps Ck at f1(p)}
f2f1: :S1S3
//

Statements:
f2f1{ the maps Ck at p}
//


2: Natural Language Description


For any C manifolds with (possibly empty) boundary, M1,M2,M3, any subsets, S1M1,S2,S2M2,S3M3, such that S2S2, any point, pS1, any natural number (including 0) or k, and any maps, f1:S1S2,f2:S2S3, such that f1 and f2 are Ck at p and f1(p), f2f1:S1S3 is Ck at p.


3: Note


It is crucial that S2 and S2 are regarded to be some subsets of the same M2: if f2 is Ck with S2 regarded as a subset of another C manifold with boundary, M2, with the same set but a different topology or a different atlas with M2, this proposition cannot be applied.

For an obvious example, for the k=0 case, if we were allowed to choose a different topology for M2, I would choose the discrete topology for M2, which would make any f2 be continuous (any map from any discrete topological space is continuous), and the proposition would imply that for whatever f2, f2f1 would be continuous, which is of course not true.

We will sometimes call a composition of Ck maps "legitimate chain of Ck maps" when the requirements for this proposition are satisfied (when S2 and S2 are regarded to be some subsets of the same M2 together with S2S2). That is because we (or at least I) tend to slip in checking the requirements.


4: Proof


Let us suppose that k=0.

f2f1 is continuous at p, by the proposition that for any maps between any topological spaces continuous at corresponding points, the composition is continuous at the point.

Let us suppose that 1k including .

There are a chart, (Uf1(p)M2,ϕf1(p)), around f1(p) and a chart, (Uf2f1(p)M3,ϕf2f1(p)), around f2f1(p) such that f2(Uf1(p)S2)Uf2f1(p) and ϕf2f1(p)f2ϕf1(p)1|ϕf1(p)(Uf1(p)S2) is Ck at ϕf1(p)(f1(p)).

As f1 is continuous at p (see Note in the definition), there is an open neighborhood, UpS1, of p on S1 such that f1(Up)Uf1(p)S2 where Up=US1 for an open subset, UM1. There is a chart, (UpM1,ϕp), around p such that UpU. f1(UpS1)f1(Up)Uf1(p)S2Uf1(p). By the proposition that for any map between any arbitrary subsets of any C manifolds with boundary Ck at point, where k excludes 0 and includes , any pair of domain chart around the point and codomain chart around the corresponding point such that the intersection of the domain chart and the domain is mapped into the codomain chart satisfies the condition of the definition, ϕf1(p)f1ϕp1|ϕp(UpS1) is Ck at ϕp(p).

f2f1(UpS1)f2(Uf1(p)S2)f2(Uf1(p)S2)Uf2f1(p). ϕf2f1(p)f2f1ϕp1|ϕp(UpS1)=ϕf2f1(p)f2ϕf1(p)1|ϕf1(p)(Uf1(p)S2)ϕf1(p)f1ϕp1|ϕp(UpS1), which is Ck at ϕp(p), by the proposition that for any maps between any arbitrary subsets of any Euclidean C manifolds Ck at corresponding points, where k includes , the composition is Ck at the point.


References


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