2025-04-13

1076: Linear Map Between Vectors Metric Spaces Induced by Norms Is Continuous iff It Is Bounded

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description/proof of that linear map between vectors metric spaces induced by norms is continuous iff it is bounded

Topics


About: vectors space
About: metric space

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that any linear map between any vectors metric spaces induced by any norms is continuous if and only if it is bounded.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Structured Description


Here is the rules of Structured Description.

Entities:
F: {R,C}, with the canonical field structure
V1: { the F vectors spaces } with the metric induced by any norm, 1
V2: { the F vectors spaces } with the metric induced by any norm, 2
f: :V1V2, { the linear maps }
//

Statements:
f{ the continuous maps }

f{ the bounded maps }
//


2: Proof


Whole Strategy: Step 1: suppose that f is bounded; Step 2: for each v1V1, take any neighborhood of f(v1), Nf(v1)V2, take any open ball around f(v1), Bf(v1),ϵV2, such that Bf(v1),ϵNf(v1), take the open ball around v1, Bv1,ϵ/cV1, where c is any constant for being bounded, and see that f(Bv1,ϵ/c)Bf(v1),ϵ; Step 3: suppose that f is continuous; Step 4: take the open ball around 0V2, B0,1V2, take an open ball around 0V1, B0,δV1, such that f(B0,δ)B0,1; Step 5: for each v1V1 such that v10, evaluate f(v1), using v1=(δ/2)/(δ/2)|v1|/|v1|v1.

Step 1:

Let us suppose that f is bounded.

Step 2:

Let v1V1 be any.

Let Nf(v1)V2 be any neighborhood of f(v1).

There is an open ball around f(v1), Bf(v1),ϵV2, such that Bf(v1),ϵNf(v1).

As f is bounded, there is a constant, cR, such that for each v1V1, f(v1)cv1.

Let us take the open ball around v1, Bv1,ϵ/cV1.

For each v1Bv1,ϵ/c, f(v1)=f(v1v1+v1)=f(v1v1)+f(v1), so, f(v1)f(v1)=f(v1v1).

f(v1)f(v1)=f(v1v1)cv1v1<cϵ/c=ϵ.

That means that f(Bv1,ϵ/c)Bf(v1),ϵNf(v1).

That means that f is continuous at v1.

As v1V1 is arbitrary, f is continuous.

Step 3:

Let us suppose that f is continuous.

Step 4:

As f is linear, f(0)=0.

Let us take the open ball around f(0)=0V2, B0,1V2.

As f is continuous, there is an open ball around 0V1, B0,δV1, such that f(B0,δ)B0,1.

Step 5:

For each v1V1 such that v10, f(v1)=f((δ/2)/(δ/2)v1/v1v1)=v1/(δ/2)f((δ/2)/v1v1)=v1/(δ/2)f((δ/2)/v1v1), but (δ/2)/v1v1B0,δ, so, f((δ/2)/v1v1)B0,1 and f(v1)<v1/(δ/2)11/(δ/2)v1.

So, c:=1/(δ/2), which does not depend on v1, makes f(v1)cv1.

So, f is bounded.


References


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