2024-03-31

517: Linear Map

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definition of linear map

Topics


About: module

The table of contents of this article


Starting Context



Target Context


  • The reader will have a definition of linear map.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Structured Description


Here is the rules of Structured Description.

Entities:
\( R\): \(\in \{\text{ the rings }\}\)
\( M_1\): \(\in \{\text{ the } R \text{ modules }\}\)
\( M_2\): \(\in \{\text{ the } R \text{ modules }\}\)
\(*f\): \(: M_1 \to M_2\)
//

Conditions:
\(\forall r_1, r_2 \in R, \forall m_1, m_2 \in M_1 (f (r_1 m_1 + r_2 m_2) = r_1 f (m_1) + r_2 f (m_2))\).
//


2: Note


The rings of \(M_1\) and \(M_2\) have to be the same in order for \(r_1 f (m_1) + r_2 f (m_2)\) to make sense; there may be an argument that the ring of \(M_2\) could be a superset of that of \(M_1\), but we do not see any immediate necessity to include that case. For example, the complex numbers field (a ring) is not exactly any superset of the real numbers field (a ring) (\(1 + 0 i \in \mathbb{C}\) and \(1 \in \mathbb{R}\) are not exactly same according to the standard definitions: intuitively speaking, \((1, 0)\) and \(1\) are not same), although there is the canonical map from \(\mathbb{R}\) into \(\mathbb{C}\).

The \(0\) element is inevitably mapped to the \(0\) element, because \(f (0) = f (0 m) = 0 f (m) = 0\) for any \(m \in M_1\).

Any linear map is nothing but a module homomorphism.


References


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