2024-10-20

823: For C Manifold with Boundary and Embedded Submanifold with Boundary, Inverse of Codomain Restricted Inclusion Is C

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description/proof of that for C manifold with boundary and embedded submanifold with boundary, inverse of codomain restricted inclusion is C

Topics


About: C manifold

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that for any C manifold with boundary and any embedded submanifold with boundary, the inverse of the codomain restricted inclusion is C.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Structured Description


Here is the rules of Structured Description.

Entities:
M: { the C manifolds with boundary }
M: { the embedded submanifolds with boundary of M}
ι: :MM, = the inclusion 
ι: :Mι(M)M, = the codomain restriction of ι
//

Statements:
ι1:ι(M)MM{ the C maps }
//


2: Note


This logic cannot be applied for immersed submanifold with boundary, which is not guaranteed to have any adopted chart or adopting chart.

ι(M) equals M sets-wise, but is just a subset of M, so, ι(M) and M need to be distinguished.

The C-ness of ι1 is according to the definition of Ck map between arbitrary subsets of C manifolds with boundary, where k includes .

An immediate corollary is that when f:NM such that f(N)ι(M) is C, f:NM, with the codomain of f replaced, is C, because f=ι1f while f:Nι(M)M and ι1:ι(M)MM are C, by the proposition that for any maps between any arbitrary subsets of any C manifolds with boundary Ck at corresponding points, where k includes , the composition is Ck at the point: f:Nι(M)M is C, by the proposition that for any map between any arbitrary subsets of any C manifolds with boundary Ck at any point, where k includes , the restriction or expansion on any codomain that contains the range is Ck at the point.

As a caveat, when one tries to prove the C-ness of f:N1MN2 by proving the C-nesses of N1M and MN2, the C-ness of N1M guarantees the C-ness of N1M by N1MM if M is really an embedded submanifold with boundary of M by this proposition, but if M is an immersed submanifold with boundary of M, the C-ness of N1M does not guarantee the C-ness of N1M, at least by this proposition.


3: Proof


Whole Strategy: do it in the 2 parts: the 1st part: suppose that M has the empty boundary; the 2nd part: suppose that M has a nonempty boundary; Step 1: suppose that M has the empty boundary; Step 2: for each mι(M), take an adopted chart, (UmM,ϕm), and the corresponding adopting chart, (UmM,ϕm), and see that ι1(Umι(M))Um; Step 3: see that ϕmι1ϕm1|ϕm(Umι(M)):ϕm(Umι(M))ϕm(Um) is C at ϕm(m); Step 4: suppose that m has a nonempty boundary; Step 5: take the double of M, D(M), which has the empty boundary, and apply the 1st part conclusion to conclude the proposition.

Step 1:

For the 1st part, let us suppose that M has the empty boundary.

The reason is that we use the slice charts criterion, which requires M to be without boundary.

Step 2:

For each mι(M), let us take an adopted chart, (UmM,ϕm), and the corresponding adopting chart, (UmM,ϕm), where Um=Umι(M) and ϕm=πJϕm|Um, where πJ:RdRd is the projection.

ι1(Umι(M))Um, obviously.

Step 3:

Whether ι1 is C at m is about whether ϕmι1ϕm1|ϕm(Umι(M)):ϕm(Umι(M))ϕm(Um) is C at ϕm(m), by the definition of Ck map between arbitrary subsets of C manifolds with boundary, where k includes .

ϕmι1ϕm1|ϕm(Umι(M)) is (x1,...,xd,0,...,0)(x1,...,xd), by the natures of adopted chart and adopting chart.

It can be extended to the C map, f:RdRd,(x1,...,xd,0,...,0)(x1,...,xd).

So, ϕmι1ϕm1|ϕm(Umι(M)) is indeed C at ϕm, and so, ι1 is C at m.

As mι(M) is arbitrary, ι1 is C all over ι(M).

Step 4:

For the 2nd part, let us suppose that M has a nonempty boundary.

Step 5:

Let us take the double of M, D(M).

D(M) is a C manifold without boundary that has a regular domain, M~, that is diffeomorphic to M.

Let a diffeomorphism be g:MM~.

Let the restriction of g be g:Mg(M):=M~M~, where M~ is the embedded submanifold with boundary of M~ that (M~) is diffeomorphic to M: it is "restriction" map-between-sets-wise, but the domain and the codomain are replaced by the C manifolds with boundary, M and M~. M~ can be indeed construed so, because while M~ is diffeomorphic to M, M~ is to M~ what M is to M.

M~ is an embedded submanifold with boundary of D(M), because M~ is an embedded submanifold with boundary (in fact, a regular domain) of D(M), by the proposition that for any C manifold with boundary, any embedded submanifold with boundary of any embedded submanifold with boundary is an embedded submanifold with boundary.

Let ι~:M~D(M) be the inclusion.

Let ι~:M~ι~(M~)D(M) be the codomain restriction of ι~.

By the 1st part conclusion, ι~1:ι~(M~)D(M)M~ is C.

Let τ~:M~D(M) be the inclusion, which is C, because M~ is an embedded submanifold with boundary of D(M).

Let τ~:M~τ~(M~)D(M) be the codomain restriction of τ~, also which is C.

ι1:ι(M)MM=g1ι~1τ~g|ι(M):ι(M)Mg(ι(M))=ι~(M~)M~τ~(ι~(M~))=ι~(M~)D(M)M~M,mg(m)τ~(g(m))=g(m)g(m)m.

As it is a composition of C maps, it is C, by the proposition that for any maps between any arbitrary subsets of any C manifolds with boundary Ck at corresponding points, where k includes , the composition is Ck at the point.


References


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