823: For Manifold with Boundary and Embedded Submanifold with Boundary, Inverse of Codomain Restricted Inclusion Is
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description/proof of that for manifold with boundary and embedded submanifold with boundary, inverse of codomain restricted inclusion is
Topics
About:
manifold
The table of contents of this article
Starting Context
Target Context
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The reader will have a description and a proof of the proposition that for any manifold with boundary and any embedded submanifold with boundary, the inverse of the codomain restricted inclusion is .
Orientation
There is a list of definitions discussed so far in this site.
There is a list of propositions discussed so far in this site.
Main Body
1: Structured Description
Here is the rules of Structured Description.
Entities:
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Statements:
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2: Note
This logic cannot be applied for immersed submanifold with boundary, which is not guaranteed to have any adopted chart or adopting chart.
equals sets-wise, but is just a subset of , so, and need to be distinguished.
The -ness of is according to the definition of map between arbitrary subsets of manifolds with boundary, where includes .
An immediate corollary is that when such that is , , with the codomain of replaced, is , because while and are , by the proposition that for any maps between any arbitrary subsets of any manifolds with boundary at corresponding points, where includes , the composition is at the point: is , by the proposition that for any map between any arbitrary subsets of any manifolds with boundary at any point, where includes , the restriction or expansion on any codomain that contains the range is at the point.
As a caveat, when one tries to prove the -ness of by proving the -nesses of and , the -ness of guarantees the -ness of by if is really an embedded submanifold with boundary of by this proposition, but if is an immersed submanifold with boundary of , the -ness of does not guarantee the -ness of , at least by this proposition.
3: Proof
Whole Strategy: do it in the 2 parts: the 1st part: suppose that has the empty boundary; the 2nd part: suppose that has a nonempty boundary; Step 1: suppose that has the empty boundary; Step 2: for each , take an adopted chart, , and the corresponding adopting chart, , and see that ; Step 3: see that is at ; Step 4: suppose that has a nonempty boundary; Step 5: take the double of , , which has the empty boundary, and apply the 1st part conclusion to conclude the proposition.
Step 1:
For the 1st part, let us suppose that has the empty boundary.
The reason is that we use the slice charts criterion, which requires to be without boundary.
Step 2:
For each , let us take an adopted chart, , and the corresponding adopting chart, , where and , where is the projection.
, obviously.
Step 3:
Whether is at is about whether is at , by the definition of map between arbitrary subsets of manifolds with boundary, where includes .
is , by the natures of adopted chart and adopting chart.
It can be extended to the map, .
So, is indeed at , and so, is at .
As is arbitrary, is all over .
Step 4:
For the 2nd part, let us suppose that has a nonempty boundary.
Step 5:
Let us take the double of , .
is a manifold without boundary that has a regular domain, , that is diffeomorphic to .
Let a diffeomorphism be .
Let the restriction of be , where is the embedded submanifold with boundary of that () is diffeomorphic to : it is "restriction" map-between-sets-wise, but the domain and the codomain are replaced by the manifolds with boundary, and . can be indeed construed so, because while is diffeomorphic to , is to what is to .
is an embedded submanifold with boundary of , because is an embedded submanifold with boundary (in fact, a regular domain) of , by the proposition that for any manifold with boundary, any embedded submanifold with boundary of any embedded submanifold with boundary is an embedded submanifold with boundary.
Let be the inclusion.
Let be the codomain restriction of .
By the 1st part conclusion, is .
Let be the inclusion, which is , because is an embedded submanifold with boundary of .
Let be the codomain restriction of , also which is .
.
As it is a composition of maps, it is , by the proposition that for any maps between any arbitrary subsets of any manifolds with boundary at corresponding points, where includes , the composition is at the point.
References
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