2025-12-14

1489: For \(C^\infty\) Map from \(C^\infty\) Manifold with Boundary into Finite-Product \(C^\infty\) Manifold with Boundary, Composition of Canonical 'Vectors Spaces - Linear Morphisms' Isomorphism after Differential Is Direct Sum of Differentials of Compositions of Projections after Map

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description/proof of that for \(C^\infty\) map from \(C^\infty\) manifold with boundary into finite-product \(C^\infty\) manifold with boundary, composition of canonical 'vectors spaces - linear morphisms' isomorphism after differential is direct sum of differentials of compositions of projections after map

Topics


About: \(C^\infty\) manifold

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that for any \(C^\infty\) map from any \(C^\infty\) manifold with boundary into any finite-product \(C^\infty\) manifold with boundary, the composition of the canonical 'vectors spaces - linear morphisms' isomorphism after the differential is the direct sum of the differentials of the compositions of the projections after the map.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Structured Description


Here is the rules of Structured Description.

Entities:
\(M\): \(\in \{\text{ the } C^\infty \text{ manifolds with boundary }\}\)
\(\{M_1, ..., M_{n - 1}\}\): \(\subseteq \{\text{ the } C^\infty \text{ manifolds }\}\)
\(M_n\): \(\in \{\text{ the } C^\infty \text{ manifolds with boundary }\}\)
\(M_1 \times ... \times M_n\): \(= \text{ the product } C^\infty \text{ manifold with boundary }\)
\(f\): \(: M \to M_1 \times ... \times M_n\), \(\in \{\text{ the } C^\infty \text{ maps }\}\)
\(\{\pi_1, ..., \pi_n\}\): \(\pi_j: M_1 \times ... \times M_n \to M_j = \text{ the projection }\)
\(d f_m\): \(: T_mM \to T_{f (m)}(M_1 \times ... \times M_n)\), \(= \text{ the differential at } m\)
\(g\): \(: T_{f (m)}(M_1 \times ... \times M_n) \to T_{f (m)^1}M_1 \oplus ... \oplus T_{f (m)^n}M_n, v \mapsto (d {\pi_1}_{f (m)} v, ..., d {\pi_n}_{f (m)} v)\), \(= \text{ the canonical 'vectors spaces - linear morphisms' isomorphism }\)
\(g \circ d f_m\): \(: T_mM \to T_{f (m)^1}M_1 \oplus ... \oplus T_{f (m)^n}M_n\)
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Statements:
\(g \circ d f_m = (d (\pi_1 \circ f)_m, ..., d (\pi_n \circ f)_m)\)
//


2: Proof


Whole Strategy: Step 1: see that \(g \circ d f_m = (d {\pi_1}_{f (m)} \circ d f_m, ..., d {\pi_n}_{f (m)} \circ d f_m)\).

Step 1:

As we already know that \(g: v \mapsto (d {\pi_1}_{f (m)} v, ..., d {\pi_n}_{f (m)} v)\), by the proposition that for any finite-product \(C^\infty\) manifold with boundary and any point, there is the 'vectors spaces - linear morphisms' isomorphism from the tangent vectors space at the point onto the direct sum of the tangent vectors spaces of the constituent manifolds with boundary at the corresponding points as the para-product of the differentials of the projections, for each \(v \in T_mM\), \(g \circ d f_m (v) = (d {\pi_1}_{f (m)} \circ d f_m (v), ..., d {\pi_n}_{f (m)} \circ d f_m (v)) = (d (\pi_1 \circ f)_m (v), ..., d (\pi_n \circ f)_m (v))\), as is well-known.

That means that \(g \circ d f_m = (d (\pi_1 \circ f)_m, ..., d (\pi_n \circ f)_m)\).


References


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