2025-01-07

933: Range of Linear Map Between Modules Is Submodule of Codomain

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description/proof of that range of linear map between modules is submodule of codomain

Topics


About: module

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that the range of any linear map between any modules is a submodule of the codomain.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Structured Description


Here is the rules of Structured Description.

Entities:
R: { the rings }
M1: { the R modules }
M2: { the R modules }
f: :M1M2, { the linear maps }


Statements:
f(M1){ the submodules of M2}
//


2: Proof


Whole Strategy: Step 1: see that f(M1) satisfies the requirements to be a module.

Step 1:

1) f(m),f(m)f(M1)(f(m)+f(m)f(M1)) (closed-ness under addition): f(m)+f(m)=f(m+m)f(M1).

2) f(m),f(m)f(M1)(f(m)+f(m)=f(m)+f(m)) (commutativity of addition): it holds on ambient M2.

3) f(m),f(m),f(m)f(M1)((f(m)+f(m))+f(m)=f(m)+(f(m)+f(m))) (associativity of additions): it holds on ambient M2.

4) 0f(M1)(f(m)f(M1)(f(m)+0=f(m))) (existence of 0 element): f(0)=0f(M1) is the one.

5) f(m)f(M1)(f(m)f(M1)(f(m)+f(m)=0)) (existence of inverse element): f(m)=f(m)f(V1) is the one.

6) f(m)f(M1),rR(r.f(m)f(M1)) (closed-ness under scalar multiplication): f(rm)=r.f(m)f(M1).

7) f(m)f(M1),r1,r2R((r1+r2).f(m)=r1.f(m)+r2.f(m)) (scalar multiplication distributability for scalars addition): it holds on ambient M2.

8) f(m),f(m)f(M1),rR(r.(f(m)+f(m))=r.f(m)+r.f(m)) (scalar multiplication distributability for elements addition): it holds on ambient M2.

9) f(m)f(M1),r1,r2R((r1r2).f(m)=r1.(r2.f(m))) (associativity of scalar multiplications): it holds on ambient M2.

10) f(m)f(M1)(1.f(m)=f(m)) (identity of 1 multiplication): it holds on ambient M2.


References


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