709: For Map from Subset of Manifold with Boundary into Subset of Manifold with Boundary, Map Is Local Diffeomorphism iff for Each Domain Point and Its Image, There Are Charts by Which Coordinates Function Is Diffeomorphism
<The previous article in this series | The table of contents of this series | The next article in this series>
description/proof of that for map from subset of manifold with boundary into subset of manifold with boundary, map is local diffeomorphism iff for each domain point and its image, there are charts by which coordinates function is diffeomorphism
Topics
About:
manifold
The table of contents of this article
Starting Context
Target Context
-
The reader will have a description and a proof of the proposition that for any map from any subset of any manifold with boundary into any subset of any manifold with boundary, the map is a local diffeomorphism if and only if for each domain point and its image, there are some charts by which the coordinates function is a diffeomorphism.
Orientation
There is a list of definitions discussed so far in this site.
There is a list of propositions discussed so far in this site.
Main Body
1: Structured Description
Here is the rules of Structured Description.
Entities:
:
:
:
:
:
//
Statements:
//
2: Natural Language Description
For any manifold with boundary, , any manifold with boundary, , any subset, , any subset, , and any map, , is a local diffeomorphisms if and only if for each , there are some charts, and , such that the coordinates function, is a diffeomorphism.
3: Proof
Whole Strategy: Step 1: suppose that is locally diffeomorphic; Step 2: for each , take an open neighborhood of , , and an open neighborhood of , , that the definition of local diffeomorphism guarantees; Step 3: take a chart, , and a chart, , that the definition of map at guarantees; Step 4: define the chart, and see that for an open neighborhood of on , ; Step 5: define the chart, ; Step 6: see that and satisfy the conditions; Step 7: suppose that there are some charts, and , that satisfy the conditions; Step 8: see that and are some open neighborhoods that the definition of local diffeomorphism requires.
Step 1:
Let us suppose that is locally diffeomorphic.
Step 2:
For each , let us take an open neighborhood of , , and an open neighborhood of , , that the definition of local diffeomorphism guarantees. That means that is diffeomorphic.
Step 3:
Especially, is at , so, let us take a chart, , and a chart, , that the definition of map at guarantees. That mean that and is at .
Step 4:
Let us define the chart, .
is an open subset of by the definition of subspace topology, and as is homeomorphic, is an open subset of , so, for an open neighborhood of , , by the definition of subspace topology.
, because , so, .
Step 5:
Let us define the chart, .
Step 6:
Let us see that and satisfy the conditions of this proposition.
is bijective, because while is injective as the restriction of the bijective , .
By the proposition that for any map between any arbitrary subsets of any manifolds with boundary at any point, where excludes and includes , any pair of domain chart around the point and codomain chart around the corresponding point such that the intersection of the domain chart and the domain is mapped into the codomain chart satisfies the condition of the definition, the and pair satisfies the condition of the definition of -ness for .
So, is .
Likewise, the and pair satisfies the condition of the definition of -ness for .
So, is .
.
So, is a diffeomorphism.
Step 7:
Let us suppose that there are some charts, and , that satisfy the conditions of this proposition.
Step 8:
is a diffeomorphism, because it is bijective and for each , there are the charts pair, and , which are some charts around and , that satisfies the conditions for ' s being at and for 's being at .
So, is locally diffeomorphic.
4: Note
's being diffeomorphic does not necessarily mean that it has a diffeomorphic extension.
References
<The previous article in this series | The table of contents of this series | The next article in this series>