2024-06-03

603: Injective Group Homomorphism Is 'Groups - Homomorphisms' Isomorphism onto Range

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description/proof of that injective group homomorphism is 'groups - homomorphisms' isomorphism onto range

Topics


About: group

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that any injective group homomorphism is a 'groups - homomorphisms' isomorphism onto the range of the homomorphism.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Structured Description


Here is the rules of Structured Description.

Entities:
\(G_1\): \(\in \{\text{ the groups }\}\)
\(G_2\): \(\in \{\text{ the groups }\}\)
\(f\): \(G_1 \to G_2\), \(\in \{\text{ the injections }\} \cap \{\text{ the group homomorphisms }\}\)
\(f'\): \(G_1 \to f (G_1)\), \(g \mapsto f (g)\)
//

Statements:
\(f (G_1) \in \{\text{ the subgroups of } G_2\}\)
\(\land\)
\(f' \in \{\text{ the 'groups - homomorphisms' isomorphisms }\}\)
//


2: Natural Language Description


For any groups, \(G_1, G_2\), and any injective group homomorphism, \(f: G_1 \to G_2\), \(f (G_1) \subseteq G_2\) is a subgroup of \(G_2\) and \(f': G_1 \to f (G_1)\) is a 'groups - homomorphisms' isomorphism.


3: Proof


\(f (G_1)\) is a subgroup of \(G_2\), by the proposition that for any group homomorphism, the range of the homomorphism is a subgroup of the codomain.

\(f'\) is a bijective group homomorphism.

So, \(f'\) is a 'groups - homomorphisms' isomorphism, by the proposition that any bijective group homomorphism is a 'groups - homomorphisms' isomorphism.


References


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