2024-03-03

493: Map Between Arbitrary Subsets of C Manifolds with Boundary Bijective and Locally Diffeomorphic at Each Point Is Diffeomorphism

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A description/proof of that map between arbitrary subsets of C manifolds with boundary bijective and locally diffeomorphic at each point is diffeomorphism

Topics


About: C manifold with boundary

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that any map between arbitrary subsets of any C manifolds with boundary bijective and locally diffeomorphic at each point is a diffeomorphism.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Description


For any C manifolds with (possibly empty) boundary, M1,M2, and any subsets, S1M1,S2M2, any map, f:S1S2, that is bijective and locally diffeomorphic at each point is a diffeomorphism.


2: Proof


As f is bijective, there is the inverse, f1:S2S1.

f is C, by the proposition that any map between arbitrary subsets of any C manifolds with boundary locally diffeomorphic at any point is C at the point.

For each f(p)S2, there are an open neighborhood, UpM1, of pS1 and an open neighborhood, Uf(p)M2, of f(p) such that f|UpS1:UpS1Uf(p)S2 is a diffeomorphism. That means that there are an open neighborhood, Uf(p)M2, of f(p) and an open neighborhood, UpM1, of p=f1(f(p))S1 such that f1|Uf(p)S2:Uf(p)S2UpS1 is a diffeomorphism, so, f1 is locally diffeomorphic at each f(p), and is C, by the proposition that any map between arbitrary subsets of any C manifolds with boundary locally diffeomorphic at any point is C at the point.

So, f is a diffeomorphism.


References


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