2023-10-01

379: Continuous Surjection Between Topological Spaces Is Quotient Map if Any Codomain Subset Is Closed if Its Preimage Is Closed

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A description/proof of that continuous surjection between topological spaces is quotient map if any codomain subset is closed if its preimage is closed

Topics


About: topological space

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that any continuous surjection between any topological spaces is a quotient map if any codomain subset is closed if its preimage is closed.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Description


For any topological spaces, T1,T2, and any continuous surjection, f:T1T2, f is a quotient map if any subset, ST2, is closed if its preimage, f1(S), is closed.


2: Proof


Let us suppose that S is closed if f1(S) is closed. For any subset, ST2, if f1(S) is open, is S open? T1f1(S) is closed. T1f1(S)=f1(T2S), by the proposition that the preimage of the codomain minus any codomain subset under any map is the domain minus the preimage of the subset. T2S is closed. S is open.


3: Note


Being continuous is required as a precondition, because the continuousness is not guaranteed by just any codomain subset's being closed if the preimage is close.


References


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