2026-09-13

1979: Inverse of Map

<The previous article in this series | The table of contents of this series | The next article in this series>

definition of inverse of map

Topics


About: set

The table of contents of this article


Starting Context



Target Context


  • The reader will have a definition of inverse of map.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Structured Description


Here is the rules of Structured Description.

Entities:
\( S_1\): \(\in \{\text{ the sets }\}\)
\( S_2\): \(\in \{\text{ the sets }\}\)
\( f\): \(: S_1 \to S_2\)
\(*f^{- 1}\): \(: S_2 \to S_1\)
//

Conditions:
\(f^{- 1} \circ f = id_{S_1} \land f \circ f^{- 1} = id_{S_2}\)
//


2: Note


For an \(f\), \(f^{- 1}\) may not exist.

For example, let \(S_1 = \mathbb{R}\), \(S_2 = \mathbb{R}\), and \(f = 0\), the constant map, then, \(f^{- 1}\) does not exist, because for each \(r \in \mathbb{R}\), \(f^{- 1} \circ f (r) = f^{- 1} (0)\), which cannot be \(id_{S_1} (r) = r\), because whatever \(f^{- 1}\) is, \(f^{- 1} (0)\) cannot be changed according to \(r\).

If \(f^{- 1}\) exists, it is unique, by the proposition that for any map, if an inverse exists, the inverse is the unique inverse, which is the reason why the inverse is denoted as \(f^{- 1}\) as though it is determined by \(f\).


References


<The previous article in this series | The table of contents of this series | The next article in this series>