2026-09-27

2008: For Module, Inverse of Nonzero Element Is Nonzero Element

<The previous article in this series | The table of contents of this series | The next article in this series>

description/proof of that for module, inverse of nonzero element is nonzero element

Topics


About: module

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that for any module, the inverse of any nonzero element is a nonzero element.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Structured Description


Here is the rules of Structured Description.

Entities:
\(R\): \(\in \{\text{ the rings }\}\)
\(M\): \(\in \{\text{ the } R \text{ modules }\}\)
\(m\): \(\in M\)
//

Statements:
\(m \neq 0\)
\(\implies\)
\(- m \neq 0\)
//


2: Proof


Whole Strategy: Step 1: suppose that \(- m = 0\) and find a contradiction.

Step 1:

\(- m\) is nothing but the inverse element of \(m\).

Let us suppose that \(- m = 0\).

\(m + (- m) = 0\), but the left hand side would be \(m + 0 = m\), so, \(m = 0\), a contradiction against that \(m \neq 0\).

So, \(- m \neq 0\).


References


<The previous article in this series | The table of contents of this series | The next article in this series>