2026-05-10

1773: Normal Topological Space Is Regular

<The previous article in this series | The table of contents of this series | The next article in this series>

description/proof of that normal topological space is regular

Topics


About: topological space

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that any normal topological space is regular.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Structured Description


Here is the rules of Structured Description.

Entities:
\(T\): \(\in \{\text{ the normal topological spaces }\}\)
//

Statements:
\(T \in \{\text{ the regular topological spaces }\}\)
//


2: Proof


Whole Strategy: Step 1: see that \(T\) satisfies the conditions to be regular.

Step 1:

\(\forall t \in T (\{t\} \in \{\text{ the closed subsets of } T\})\) is directly required by the definition of normal topological space.

Let \(t \in T\) be any.

Let \(C \subseteq T\) be any closed subset such that \(t \notin C\).

\(\{t\} \subseteq T\) is closed.

\(\{t\} \cap C = \emptyset\).

There are an open neighborhood of \(\{t\}\), \(U_{\{t\}} \subseteq T\), and an open neighborhood of \(C\), \(U_C \subseteq T\), such that \(U_{\{t\}} \cap U_C = \emptyset\).

But \(U_{\{t\}}\) is an open neighborhood of \(t\).

So, \(T\) is regular.


References


<The previous article in this series | The table of contents of this series | The next article in this series>