2026-03-22

1684: Constant Map Between Topological Spaces Is Continuous

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description/proof of that constant map between topological spaces is continuous

Topics


About: topological space

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that any constant map between any topological spaces is continuous.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Structured Description


Here is the rules of Structured Description.

Entities:
\(T_1\): \(\in \{\text{ the topological spaces }\}\)
\(T_2\): \(\in \{\text{ the topological spaces }\}\)
\(f\): \(: T_1 \to T_2\)
//

Statements:
\(\exists t_0 \in T_2 (\forall t \in T_1 (f (t) = t_0))\)
\(\implies\)
\(f \in \{\text{ the continuous maps }\}\)
//


2: Proof


Whole Strategy: Step 1: see that for each \(t \in T_1\), \(f\) is continuous at \(t\).

Step 1:

Let \(t \in T_1\) be any.

\(f (t) = t_0\).

Let \(U_{t_0} \subseteq T_2\) be any open neighborhood of \(t_0\) on \(T_2\).

\(T_1\) is an open neighborhood of \(t\) on \(T_1\) and \(f (T_1) = \{t_0\} \subseteq U_{t_0}\).

So, \(f\) is continuous at \(t\).

As \(t\) is arbitrary, \(f\) is continuous.


References


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