description/proof of that for
Topics
About:
The table of contents of this article
Starting Context
-
The reader knows a definition of
vectors subbundle of rank of vectors bundle of rank . -
The reader admits the proposition that for any
vectors bundle and any set of local sections over any open domain that is linearly independent, of each point of the domain, there is a possibly smaller open neighborhood over which there is a local frame that contains the restricted sections set. -
The reader admits the proposition that for any
vectors bundle, any frame exists over and only over any trivializing open subset. -
The reader admits the proposition that for any
vectors bundle, a trivializing open subset is not necessarily a chart open subset, but there is a possibly smaller chart trivializing open subset at each point on any trivializing open subset. -
The reader admits the proposition that for any
vectors bundle, the trivialization of any chart trivializing open subset induces the canonical chart map. -
The reader admits the proposition that any subset of any
manifold with boundary that satisfies the local-slice condition is an embedded submanifold with boundary of the manifold with boundary with the subspace topology and the adopting atlas.
Target Context
-
The reader will have a description and a proof of the proposition that for any
vectors bundle, the union of any -dimensional vectors subspaces of the fibers that allows any local frames is a vectors subbundle with the subspace topology and the adopting atlas.
Orientation
There is a list of definitions discussed so far in this site.
There is a list of propositions discussed so far in this site.
Main Body
1: Structured Description
Here is the rules of Structured Description.
Entities:
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Statements:
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2: Proof
Whole Strategy: Step 1: take a trivializing chart around
Step 1:
There are an open neighborhood of
There is a trivializing chart around
Step 2:
Let us take the chart induced by the trivialization,
Let us see that the chart is an adopted chart for
It is about that there are a
Let
So,
So,
So,
So,
Step 3:
Let us see that
For each
Step 4:
So,