2025-03-30

1057: Topological Space Induced by Metric Is Hausdorff

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description/proof of that topological space induced by metric is Hausdorff

Topics


About: topological space

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that the topological space induced by any metric is Hausdorff.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Structured Description


Here is the rules of Structured Description.

Entities:
T: { the topological spaces }, induced by any metric, dist:T×TR
//

Statements:
T{ the Hausdorff topological spaces }
//


2: Proof


Whole Strategy: Step 1: for each t,tT such that tt, take the open neighborhood of t, Bt,dist(t,t)/2, and the open neighborhood of t, Bt,dist(t,t)/2,, and see that Bt,dist(t,t)/2Bt,dist(t,t)/2=.

Step 1:

Let t,tT be any such that tt.

0<dist(t,t).

Let us take the open neighborhood of t, Bt,dist(t,t)/2, and the open neighborhood of t, Bt,dist(t,t)/2,.

Let us see that Bt,dist(t,t)/2Bt,dist(t,t)/2=.

Let uBt,dist(t,t)/2 be any.

dist(t,t)dist(t,u)+dist(u,t), so, dist(t,t)dist(t,u)dist(u,t), but dist(t,t)/2=dist(t,t)dist(t,t)/2<dist(t,t)dist(t,u), so, dist(t,t)/2<dist(u,t), which means that uBt,dist(t,t)/2.

So, Bt,dist(t,t)/2Bt,dist(t,t)/2=.


References


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