2025-03-30

1051: For Map from Topological Space Minus Point into Finite-Dimensional Real Vectors Space with Canonical Topology, Convergence of Map w.r.t. Point Exists if Convergences of Coefficients w.r.t. Constant Vectors w.r.t. Point Exist, and Then, Convergence Is Expressed with Convergences

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description/proof of that for map from topological space minus point into finite-dimensional real vectors space with canonical topology, convergence of map w.r.t. point exists if convergences of coefficients w.r.t. constant vectors w.r.t. point exist, and then, convergence is expressed with convergences

Topics


About: topological space

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that for any map from any topological space minus any point into any finite-dimensional real vectors space with the canonical topology, the convergence of the map with respect to the point exists if the convergences of the coefficients with respect to any constant vectors with respect to the point exist, and then, the convergence is expressed with the convergences.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Structured Description


Here is the rules of Structured Description.

Entities:
T: { the topological spaces }
V: { the d -dimensional R vectors spaces }, with the canonical topology
{v1,...,vn}: V
t: T
f: :T{t}V,tfj(t)vj
//

Statements:
(
j{1,...,n}(limttfj(t))

limttf(t)
)

limttf(t)=limttfj(t)vj
//


2: Note


The reverse does not necessarily hold: for example, when T=R, t=0, and f(t)=cos(1/t)vcos(1/t)v, f(t)=0, so, f converges with respect to 0, but cos(1/t) does not converge with respect to 0.

Compare with the proposition that for any map from any topological space minus any point into any finite-dimensional real vectors space with the canonical topology, the convergence of the map with respect to the point exists if and only if the convergences of the component maps (with respect to any basis) with respect to the point exist, and then, the convergence Is expressed with the convergences.


3: Proof


Whole Strategy: Step 1: suppose that limttfj(t) exists and denote it as vj; Step 2: see that limttf(t) exists and equals vjvj.

Step 0:

Note that V is Hausdorff.

Note that supposing the existence of limttfj(t) implies that {t}T is not open, because otherwise, the convergences would not be unique: refer to Note for the definition of convergence of map from topological space minus point into topological space with respect to point.

So, we do not need to worry about the uniqueness of convergences.

Step 1:

Let us suppose that for each j{1,...,n}, limttfj(t) exists and denote it as vj.

Step 2:

Let B={b1,..,bd} be any basis for V.

vj=vjlbl.

f(t)=fj(t)vj=fj(t)vjlbl.

As fj(t) converges with respect to t, for each l{1,...,d}, fj(t)vjl converges to vjvjl with respect to t.

By the proposition that for any map from any topological space minus any point into any finite-dimensional real vectors space with the canonical topology, the convergence of the map with respect to the point exists if and only if the convergences of the component maps (with respect to any basis) with respect to the point exist, and then, the convergence Is expressed with the convergences, limttf(t) exists and equals vjvjlbl.

vjvjlbl=vjvj.

So, limttf(t)=vjvj=limttfj(t)vj.


References


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