2024-11-25

871: Normalizer of Subgroup on Group

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definition of normalizer of subgroup on group

Topics


About: group

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Starting Context



Target Context


  • The reader will have a definition of normalizer of subgroup on group.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Structured Description


Here is the rules of Structured Description.

Entities:
\( G'\): \(\in \{\text{ the groups }\}\)
\( G\): \(\in \{\text{ the subgroups of } G'\}\)
\(*N_{G'} (G)\): \(= \{g' \in G' \vert g' G g'^{-1} = G\}\)
//

Conditions:
//


2: Note


The name has originated from the fact that \(N_{G'} (G)\) is the largest subgroup of \(G'\) of which (\(N_{G'} (G)\)) \(G\) is a normal subgroup.

Let us confirm the fact.

Let us see that \(N_{G'} (G)\) is a group.

For each \(h_1, h_2 \in N_{G'} (G)\), \(h_1 h_2 \in N_{G'} (G)\), because \(h_1 h_2 G (h_1 h_2)^{-1} = h_1 h_2 G {h_2}^{-1} {h_1}^{-1} = h_1 G {h_1}^{-1} = G\).

\(1 \in N_{G'} (G)\), because \(1 G 1^{-1} = G\).

For each \(h \in N_{G'} (G)\), \(h^{-1} \in N_{G'} (G)\), because \(h^{-1} G h = h^{-1} (h G h^{-1}) h = (h^{-1} h) G (h^{-1} h) = 1 G 1 = G\).

Associativity holds because it holds in the ambient \(G'\).

\(G \subseteq N_{G'} (G)\), because for each \(g \in G\), \(g G g^{-1} = G\).

\(G\) is a normal subgroup of \(N_{G'} (G)\), because for each \(h \in N_{G'} (G)\), \(h G h^{-1}\).

\(N_{G'} (G)\) is such the largest, because if there is a subgroup of \(G'\), \(G''\), such that \(G\) is a normal subgroup of \(G''\), for each \(g'' \in G''\), \(g'' G g''^{-1} = G\), which means that \(g'' \in N_{G'} (G)\), which means that \(G'' \subseteq N_{G'} (G)\).


References


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