864: For Manifold with Boundary and Embedded Submanifold with Boundary, Around Each Point on Submanifold with Boundary, There Is Trivializing Open Subset for Manifold with Boundary Whose Intersection with Submanifold with Boundary Is Chart Domain
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description/proof of that for manifold with boundary and embedded submanifold with boundary, around each point on submanifold with boundary, there is trivializing open subset for manifold with boundary whose intersection with submanifold with boundary is chart domain
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manifold
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Starting Context
Target Context
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The reader will have a description and a proof of the proposition that for any manifold with boundary and its any embedded submanifold with boundary, around each point on the submanifold with boundary, there is a trivializing open subset for the manifold with boundary whose intersection with the submanifold with boundary is a chart domain for the submanifold with boundary.
Orientation
There is a list of definitions discussed so far in this site.
There is a list of propositions discussed so far in this site.
Main Body
1: Structured Description
Here is the rules of Structured Description.
Entities:
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Statements:
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2: Note
The point is that can be with a nonempty boundary: when is without boundary, the slice charts theorem can be used to have as an adopted chart domain; this proposition says that even when has a nonempty boundary, a , which is not necessarily any chart domain, can be chosen.
3: Proof
Whole Strategy: Step 1: take any trivializing open subset around for , ; Step 2: take any open neighborhood of on , , whose inclusion is contained in , and take any chart domain contained in , ; Step 3: let , take and , and see that is a trivializing open subset for and is a chart domain for .
Step 1:
Let us take any trivializing open subset around for , .
Step 2:
Let be the inclusion.
As is continuous, there is an open neighborhood of on , , such that .
There is a chart domain contained in , , such that , because while there is a chart domain around , the intersection of the chart domain and is a chart domain, by the proposition that for any manifold with boundary and its any chart, the restriction of the chart on any open subset domain is a chart, and the intersection can be .
Step 3:
As has the subspace topology of , where is an open neighborhood of on .
Let us take and .
As is an open subset of , is a trivializing open subset for , by the proposition that any open subset of any trivializing open subset is a trivializing open subset.
As is an open subset of ( is a topological subspace of and is open on ), is a chart domain, by the proposition that for any manifold with boundary and its any chart, the restriction of the chart on any open subset domain is a chart.
References
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