2024-08-25

739: Motion

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definition of motion

Topics


About: vectors space

The table of contents of this article


Starting Context



Target Context


  • The reader will have a definition of motion.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Structured Description


Here is the rules of Structured Description.

Entities:
\( F_1\): \(\in \{\mathbb{R}, \mathbb{C}\}\), with the canonical field structure
\( F_2\): \(\in \{\mathbb{R}, \mathbb{C}\}\), with the canonical field structure
\( V_1\): \(\in \{\text{ the normed } F_1 \text{ vectors spaces }\}\)
\( V_2\): \(\in \{\text{ the normed } F_2 \text{ vectors spaces }\}\)
\(*f\): \(: V_1 \to V_2\)
//

Conditions:
\(\forall v, v' \in V_1 (\Vert v - v' \Vert = \Vert f (v) - f (v') \Vert)\)
//


2: Natural Language Description


For any \(F_1 \in \{\mathbb{R}, \mathbb{C}\}\), with the canonical field structure, any \(F_2 \in \{\mathbb{R}, \mathbb{C}\}\), with the canonical field structure, any normed \(F_1\) vectors space, \(V_1\), and any normed \(F_2\) vectors space, \(V_2\), any map, \(f: V_1 \to V_2\), such that \(\forall v, v' \in V_1 (\Vert v - v' \Vert = \Vert f (v) - f (v') \Vert)\)


3: Note


\(f\) is not linear in general. For example, \(V_1\) and \(V_2\) are the Euclidean normed vectors spaces, \(\mathbb{R}^n\), and the translation, \(f: v \mapsto v + v_0\), where \(v_0 \neq 0\), is a motion, which is not linear, because \(f (0) = v_0\), so, \(f (r 0) = f (0) = v_0 \neq r v_0 = r f (0)\).

\(F_1\) and \(F_2\) do not need to be the same, because \(f\) is not supposed to be linear.

It is \(\Vert f (v) - f (v') \Vert\) not \(\Vert f (v - v') \Vert\): they can be different, because \(f\) is not linear in general. For example, \(V_1\) and \(V_2\) are the Euclidean normed vectors spaces, \(\mathbb{R}^n\), and for the translation, \(f: v \mapsto v + v_0\), where \(v_0 \neq 0\), \(\Vert v - v \Vert = \Vert 0 \Vert = 0 \neq \Vert v_0 \Vert = \Vert f (0) \Vert = \Vert f (v - v) \Vert\).


References


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