391: Topological Space Is Countably Compact if It Is Sequentially Compact
<The previous article in this series | The table of contents of this series | The next article in this series>
A description/proof of that topological space is countably compact if it is sequentially compact
Topics
About:
topological space
The table of contents of this article
Starting Context
Target Context
-
The reader will have a description and a proof of the proposition that any topological space is countably compact if the space is sequentially compact.
Orientation
There is a list of definitions discussed so far in this site.
There is a list of propositions discussed so far in this site.
Main Body
1: Description
Any topological space, , is countably compact if is sequentially compact.
2: Proof
Let suppose that is sequentially compact. We will prove that each infinite subset, , has an -accumulation point, , which will imply that is countably compact, by the proposition that any topological space is countably compact if and only if each infinite subset has an -accumulation point.
Let any infinite subset be . Let us choose any sequence of points from , , which is possible because is infinite. There is a subsequence, , that converges to a point, . is an -accumulation point of , because for any neighborhood, , there is an such that for each such that , which means that is infinite.
3: Note
The converse is not true in general. The converse with the requirement that is 1st-countable is true, as is proved in another article.
References
<The previous article in this series | The table of contents of this series | The next article in this series>