2023-09-17

369: C^\infty Function on C^\infty Manifold Is C^\infty on Regular Submanifold

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A description/proof of that \(C^\infty\) function on \(C^\infty\) manifold is \(C^\infty\) on regular submanifold

Topics


About: \(C^\infty\) manifold

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that for any \(C^\infty\) manifold and its any regular submanifold, any \(C^\infty\) function on the super manifold is \(C^\infty\) on the regular submanifold.

Orientation


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There is a list of propositions discussed so far in this site.


Main Body


1: Description


For any \(C^\infty\) manifold, \(M'\), and any regular submanifold, \(M \subseteq M'\), any \(C^\infty\) function, \(f: M' \rightarrow \mathbb{R}\), is \(C^\infty\) on \(M\), which means that the restriction, \(f\vert_M: M \rightarrow \mathbb{R}\) is \(C^\infty\).


2: Proof


For any \(p \in M\), there is an adopted chart, \((U'_p \subseteq M', \phi'_p)\), and \(f \circ {\phi'_p}^{-1}\) is \(C^\infty\). There is the corresponding adopting chart, \((U_p, \phi_p)\), and \(f\vert_M \circ {\phi_p}^{-1}\) is \(C^\infty\), because \(f\vert_M \circ {\phi_p}^{-1} (r^1, r^2., ..., r^{d}) = f \circ {\phi'_p}^{-1} (r^1, r^2., ..., r^{d}, 0, ..., 0)\).


References


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