318: Topological Sum of Paracompact Topological Spaces Is Paracompact
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A description/proof of that topological sum of paracompact topological spaces is paracompact
Topics
About:
topological space
The table of contents of this article
Starting Context
Target Context
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The reader will have a description and a proof of the proposition that the topological sum of any possibly uncountable number of paracompact topological spaces is paracompact.
Orientation
There is a list of definitions discussed so far in this site.
There is a list of propositions discussed so far in this site.
Main Body
1: Description
For any paracompact topological spaces, where is a possibly uncountable indices set, the topological sum, , is paracompact.
2: Proof
is a Hausdorff topological space as the topological sum of Hausdorff topological spaces, by the proposition that the topological sum of any possibly uncountable number of Hausdorff topological spaces is Hausdorff.
For any open cover, where is any possibly uncountable indices set, of , is an open cover of . As is paracompact, there is a locally finite refinement, where is a possibly uncountable indices set. is a locally finite refinement of , because is open on , covers , , and around any point, , , and there is a neighborhood, , contained in that intersects only finite elements of , because is open and disjoint from any such that .
3: Note
When is any Hausdorff topological space that is the disjoint union of any possibly uncountable number of open paracompact subspaces, is paracompact, because is the topological sum of the subspaces.
The subspaces have to be open and disjoint in order to apply this proposition, because otherwise, would not be any topological sum.
References
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