2023-07-02

318: Topological Sum of Paracompact Topological Spaces Is Paracompact

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A description/proof of that topological sum of paracompact topological spaces is paracompact

Topics


About: topological space

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that the topological sum of any possibly uncountable number of paracompact topological spaces is paracompact.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Description


For any paracompact topological spaces, {Tα|αA} where A is a possibly uncountable indices set, the topological sum, T:=αTα, is paracompact.


2: Proof


T is a Hausdorff topological space as the topological sum of Hausdorff topological spaces, by the proposition that the topological sum of any possibly uncountable number of Hausdorff topological spaces is Hausdorff.

For any open cover, S:={UβT|βB} where B is any possibly uncountable indices set, of T, Sα:={UβTα|βB} is an open cover of Tα. As Tα is paracompact, there is a locally finite refinement, Sα:={UαγUβTα|γC} where C is a possibly uncountable indices set. αSα is a locally finite refinement of S, because Uαγ is open on T, αSα covers T, UαγUβ, and around any point, pT, pTα, and there is a neighborhood, Np, contained in Tα that intersects only finite elements of Sα, because Tα is open and disjoint from any Tβ such that βα.


3: Note


When T is any Hausdorff topological space that is the disjoint union of any possibly uncountable number of open paracompact subspaces, T is paracompact, because T is the topological sum of the subspaces.

The subspaces have to be open and disjoint in order to apply this proposition, because otherwise, T would not be any topological sum.


References


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