2023-06-04

296: For Topological Space, Subset of Compact Subset Is Not Necessarily Compact

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A description/proof of that for topological space, subset of compact subset is not necessarily compact

Topics


About: topological space

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that for a topological space, a subset of a compact subset is not necessarily compact.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Description


For a topological space, \(T\), and a compact subset, \(S \subseteq T\), a subset, \(S_1 \subseteq S\), is not necessarily compact on \(T\).


2: Proof


A counterexample suffices. Take \(T = \mathbb{R}^2\) with the Euclidean topology, \(S = \overline{B_{p-\epsilon}}\), and \(S_1 = B_{p-\epsilon}\) where \(B_{p-\epsilon}\) is the \(\epsilon\)-radius open ball centered at \(p\) and the over line denotes the closure.


3: Note


The word, "compact", may sound like about being small, but a smaller subset of a compact subset is not necessarily compact.


References


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