2023-06-11

301: For Topological Space and Point on Subspace, Intersection of Neighborhood of Point on Base Space and Subspace Is Neighborhood on Subspace

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A description/proof of that for topological space and point on subspace, intersection of neighborhood of point on base space and subspace is neighborhood on subspace

Topics


About: topological space

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that for any topological space and any point on any subspace, the intersection of any neighborhood of the point on the base space and the subspace is a neighborhood on the subspace.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Description


For any topological space, \(T\), any subspace, \(T_1 \subseteq T\), any point, \(p \in T_1\), and any neighborhood, \(N_p \subseteq T\), of \(p\) on \(T\), \(N_p \cap T_1\) is a neighborhood of \(p\) on \(T_1\).


2: Proof


\(p \in N_p \cap T_1\). There is an open neighborhood, \(U_p \subseteq N_p\), of \(p\) on \(T\). \(U_p \cap T_1 \subseteq N_p \cap T_1\) is an open neighborhood of \(p\) on \(T_1\), because \(p \in U_p \cap T_1\) and \(U_p \cap T_1\) is open on \(T_1\).


References


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