2023-02-05

190: Subset Is Contained in Map Preimage of Image of Subset

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A description/proof of that subset is contained in map preimage of image of subset

Topics


About: set

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that for any map between sets, any subset is contained in the preimage of the image of the subset.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Description


For any sets, \(S_1, S_2\), any map, \(f: S_1 \rightarrow S_2\), and any subset, \(S_3 \subseteq S_1\), such that \(S_4 = f (S_3)\), \(S_3 \subseteq f^{-1} (S_4)\).


2: Proof


For any \(p \in S_3\), \(f (p) \in S_4\), so, \(p \in f^{-1} (S_4)\).


3: Note


The subset does not necessarily equal the preimage, as \(f\) may not be injective and a point not on \(S_3\) may map into \(S_4\).


References


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