2023-01-29

404: Map Preimages of Disjoint Subsets Are Disjoint

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A description/proof of that map preimages of disjoint subsets are disjoint

Topics


About: set

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that the preimages of any disjoint subsets under any map are disjoint.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Description


For any sets, \(S_1, S_2\), any map, \(f: S_1 \rightarrow S_2\), and any disjoint subsets, \(S_{21}, S_{22} \subseteq S_2\), such that \(S_{21} \cap S_{22} = \emptyset\), \(f^{-1} (S_{21}) \cap f^{-1} (S_{22}) = \emptyset\).


2: Proof


Suppose that there was a common element, \(p \in f^{-1} (S_{21})\) and \(p \in f^{-1} (S_{22})\). \(f (p) \in S_{21}\) and \(f (p) \in S_{22}\), a contradiction.


References


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