2022-08-28

342: Absolute Difference Between Complex Numbers Is or Above Difference Between Absolute Differences with Additional Complex Number

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A description/proof of that absolute difference between complex numbers is or above difference between absolute differences with additional complex number

Topics


About: complex number

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that the absolute difference between any complex numbers is or above the difference between the absolute difference between one and any additional complex number and the absolute difference between the other and the additional number.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Description


For any complex numbers, \(c_1\) and \(c_2\), \(|c_1 - c_2| \geq |c_1 - c_3| - |c_2 - c_3|\) with any complex number, \(c_3\).


2: Proof


For any complex numbers, \(c_4\) and \(c_5\), \(|c_4| + |c_5| \geq |c_4 + c_5|\). So, \(|c_4| \geq |c_4 + c_5| - |c_5|\). But any complex numbers, \(c_1\) and \(c_2\), can be chosen such that \(c_4 = c_1 - c_2\) as \(c_4\) is arbitrary, then, \(|c_1 - c_2| \geq |c_1 - c_2 + c_5| - |c_5| \implies |c_1 - c_2| \geq |c_1 - (c_2 - c_5)| - |c_2 - (c_2 - c_5)|\), so define \(c_3 := c_2 - c_5\), which can be any complex number because \(c_5\) is arbitrary, so, \(|c_1 - c_2| \geq |c_1 - c_3| - |c_2 - c_3|\) for any complex numbers, \(c_1\), \(c_2\), and \(c_3\).


3: Note


As any real number is a complex number, this proposition holds also for real numbers.


References


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