354: Area of Hyperrectangle Can Be Approximated by Area of Covering Finite Number Hypersquares to Any Precision
<The previous article in this series | The table of contents of this series | The next article in this series>
A description/proof of that area of hyperrectangle can be approximated by area of covering finite number hypersquares to any precision
Topics
About:
Euclidean metric space
The table of contents of this article
Starting Context
Target Context
-
The reader will have a description and a proof of the proposition that the area of any hyperrectangle can be approximated by the area of covering finite number hypersquares to any precision.
Orientation
There is a list of definitions discussed so far in this site.
There is a list of propositions discussed so far in this site.
Main Body
1: Description
The area, , of any hyperrectangle on any Euclidean metric space can be approximated by the area of some finite number of hypersquares, , that cover the hyperrectangle, to any precision, which is, for any real number , .
2: Proof
Denote the side lengths of the hyperrectangle as . For any real number, , and each side index, , there is the non-negative unique integer, , and the unique real number, , such that , which means that the length is covered by times with the excess, , where the unique existences are clear based on the meaning.
Now, is the side length of the same-size hypersquares that cover the hyperrectangle, starting from a vertex of the hyperrectangle, times for each direction, with the excess of for the direction.
The excess area is the error of the approximation, which is . But by directly calculating the excess area, , adding some areas multiple times. Assuming (which we are free to do) , .
As depends only the configuration of the hyperrectangle, we choose as , then, .
References
<The previous article in this series | The table of contents of this series | The next article in this series>