2022-09-25

354: Area of Hyperrectangle Can Be Approximated by Area of Covering Finite Number Hypersquares to Any Precision

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A description/proof of that area of hyperrectangle can be approximated by area of covering finite number hypersquares to any precision

Topics


About: Euclidean metric space

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that the area of any hyperrectangle can be approximated by the area of covering finite number hypersquares to any precision.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Description


The area, a, of any hyperrectangle on any Rn Euclidean metric space can be approximated by the area of some finite number of hypersquares, ai, that cover the hyperrectangle, to any precision, which is, for any real number ϵ>0, iaia<ϵ.


2: Proof


Denote the side lengths of the hyperrectangle as l1,l2,...,ln. For any real number, ls>0, and each side index, 1in, there is the non-negative unique integer, ki(ls), and the unique real number, 0li(ls)<ls, such that ki(ls)ls=li(ls)+li, which means that the li length is covered by ki(ls) times ls with the excess, li(ls), where the unique existences are clear based on the meaning.

Now, ls is the side length of the same-size hypersquares that cover the hyperrectangle, starting from a vertex of the hyperrectangle, ki(ls) times for each i direction, with the excess of li(ls) for the i direction.

The excess area is the error of the approximation, which is e(ls)=ilski(ls)ili. But by directly calculating the excess area, e(ls)<ili(ls)ji(lj(ls)+lj), adding some areas multiple times. Assuming ls1 (which we are free to do) , ili(ls)ji(lj(ls)+lj)<ilsji(ls+lj)<lsiji(1+lj).

As L:=iji(1+lj) depends only the configuration of the hyperrectangle, we choose ls as min(1,ϵL), then, e(ls)<lsLϵ.


References


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