2022-08-07

330: Composition of Map After Preimage Is Contained in Argument Set

<The previous article in this series | The table of contents of this series | The next article in this series>

A description/proof of that composition of map after preimage is contained in argument set

Topics


About: set
About: map

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that for any map between sets, the composition of the map after any preimage is contained in the argument set.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Description


For any sets, \(S_1, S_2\), any map, \(f: S_1 \rightarrow S_2\), and any subset, \(S_3 \subseteq S_2\), \(f \circ f^{-1} (S_3) \subseteq S_3\).


2: Proof


For any \(p \in f \circ f^{-1} (S_3)\), \(p = f \circ f^{-1} (p')\) for a point, \(p' \in S_3\), but \(p = f \circ f^{-1} (p') = p'\), so, \(p \in S_3\).


3: Note


It is not necessarily \(f \circ f^{-1} (S_3) = S_3\), as for which, there is another proposition.


References


<The previous article in this series | The table of contents of this series | The next article in this series>