2022-05-01

282: Map Preimage of Whole Range Is Whole Domain

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A description/proof of that map preimage of whole range is whole domain

Topics


About: set
About: map

The table of contents of this article


Starting Context



Target Context


  • The reader will have a description and a proof of the proposition that the preimage of the whole range of any map is the whole domain.

Orientation


There is a list of definitions discussed so far in this site.

There is a list of propositions discussed so far in this site.


Main Body


1: Description


For any sets, \(S_1\) and \(S_2\), and any map, \(f: S_1 \rightarrow S_2\), the preimage of the whole range is the whole domain, which is \(f^{-1} (S_2) = S_1\).


2: Proof


Suppose \(p \in f^{-1} (S_2)\). \(p \in S_1\). Suppose \(p \in S_1\). \(f (p) \in S_2\), so \(p \in f^{-1} (S_2)\).


3: Note


The point is that the map does not have to be surjective.


References


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